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08-10-2021
Mathematics

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So, I have a math problem, the problem is,16x^0+2x^2*y^-1,How do I solve if x = 2 and y = 4?

Respuesta :

shahrearabedin shahrearabedin

08-10-2021

Answer:

Given x = 2 and y =4

so 16[tex]x^{0}[/tex]+2[tex]x^{2}[/tex][tex]y^{-1}[/tex]

= 16*[tex]2^{0}[/tex] + 2*[tex]2^{2}[/tex]*[tex]4^{-1}[/tex]

= 16 + (2*4)/4

=16 + 8/2

16 + 2

=18

Step-by-step explanation:

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