HRLP PLZ
Rectangle ABCD nas vertices A(-1, 6), B(-5, 3). C(1, - 5), and D(5, - 2).
Enter your answers in the boxes.
What is the length of AB?
units
What is the length of BC?
units
What is the area of rectangle ABCD?
units?

Respuesta :

[tex]\\ \sf\longmapsto AB=\sqrt{(-5+1)^2+(3-6)^2}[/tex]

[tex]\\ \sf\longmapsto AB=\sqrt{(-4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5[/tex]

And

[tex]\\ \sf\longmapsto BC=\sqrt{(1+5)^2+(-5-3)^2}=\sqrt{(6)^2+(-8)^2}=\sqrt{36+64}=\sqrt{100}=10[/tex]

Then

Area:-

[tex]\\ \sf\longmapsto AB(BC)[/tex]

[tex]\\ \sf\longmapsto 5(10)=50units^2[/tex]

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