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A 0.035-kg bullet is fired vertically at 214 m/s into a 0.15-kg baseball that is initially at rest. How high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball

Respuesta :

Answer:

Explanation:

conservation of momentum during the collision

0.035(214) + 0.15(0) = 0.185v

v = 40.486 m/s

The kinetic energy after impact will convert to gravity potential energy

(ignoring air resistance)

mgh = Β½mvΒ²

Β  Β  Β h = vΒ²/2g

Β  Β  Β h = 40.486Β² / (2(9.8))

Β  Β  Β h = 83.6303...

Β  Β  Β h = 84 m

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