Taking into account the reaction stoichiometry, 6.15 grams of COâ‚‚ are formed when 8.94 grams of Oâ‚‚ reacts completely.
In first place, the balanced reaction is:
CH₄ + 2 O₂  → CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is: Â
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Then the following rule of three can be applied: if by reaction stoichiometry 64 grams of Oâ‚‚ form 44.01 grams of COâ‚‚, 8.94 grams of Oâ‚‚ form how much mass of COâ‚‚?
[tex]mass of CO_{2} =\frac{8.94 grams of O_{2} x44.01 grams of CO_{2} }{64 grams of O_{2}}[/tex]
mass of COâ‚‚= 6.15 grams
Finally, 6.15 grams of COâ‚‚ are formed when 8.94 grams of Oâ‚‚ reacts completely.
Learn more about reaction stoichiometry: Â