Respuesta :

apologiabiology
remember

the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/((g(x))^2)

deritivive of lnx is 1/x
derivitive of t^2=2t

so

[tex] \frac{(1/t)t^2-2tlnt}{(t^2)^2} [/tex]=
[tex]\frac{t-2tlnt}{t^4} [/tex]=
[tex] \frac{1-2ln(t)}{t^3} [/tex]