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Consider this reaction:

FeCl2 + 2NaOH → Fe(OH)2(s) + 2NaCl If 507 g

FeCl2 were used up in the reaction, how many grams of NaCl would be made?

A. 233.76 g NaCl
B. 649.05 g Naci
C. 467.52 g NaCl
D. 1014 g Naci​

Respuesta :

biplavlama72

Answer:

C. 467.52 g NaCI is the answer.

indrawboy

mol FeCl₂ = mass : molar mass = 507 : 127 = 3.992

mol NaCl = 2/1 x mol FeCl₂ = 2/1 x 3.992 = 7.984

mass NaCl = 7.984 x 58.5 = 467.06

closest to C. 467.52 g NaCl

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