The length of a rectangle is 2cm greater than the width. If the width is increased by 4cm, the area is increased by 88cm^2. Find the original dimensions of the rectangle

Respuesta :

Step-by-step explanation:

l = length

w = width

l = w + 2

l×w = area = (w + 2)×w = w² + 2w

l×(w + 4) = area + 88

(w + 2)×(w + 4) = w² + 2w + 88

w² + 6w + 8 = w² + 2w + 88

6w + 8 = 2w + 88

4w = 80

w = 20 cm

l = w + 2 = 20 + 2 = 22 cm

the original length is 22 cm.

the original width is 20 cm.

the original area (22×20) is therefore 440 cm².

the new area (22×24) would be 528 cm².