Respuesta :

Copperdawg07
The answer is “D. UUG —> CUG”

By looking at the chart, UUG is the code for “Leu”. CUG is also the code for “Leu”. This proves that the mutation of UUG —> CUG is most likely to be selectively neutral, because the codon stays the same!

I hope this was helpful!

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