Answer: Graph the parabola y=x2β7x+2 .
Compare the equation with y=ax2+bx+c to find the values of a , b , and c .
Here, a=1,b=β7 and c=2 .
Use the values of the coefficients to write the equation of axis of symmetry .
The graph of a quadratic equation in the form Β y=ax2+bx+c has as its axis of symmetry the line x=βb2a . So, the equation of the axis of symmetry of the given parabola is x=β(β7)2(1) or x=72 .
Substitute x=72 in the equation to find the y -coordinate of the vertex.
y=(72)2β7(72)+2 Β Β =494β492+2 Β Β =49βββ98β+β84 Β Β β=β414
Therefore, the coordinates of the vertex are (72,β414) .
Now, substitute a few more x -values in the equation to get the corresponding y -values.
x y=x2β7x+2
0 2
1 β4
2 β8
3 β10
5 β8
7 2
Plot the points and join them to get the parabola
in short terms D.