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36.4 g of SnCl2 is dissolved in 135.7 mL of water.

Molar mass of SnCl2 = ____ g/mol

Liters of solution = ___ L

What is the concentration of this solution? ____ M (Answer with 3 significant figures)

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Answers:

1st: 189.6 g/mol

2nd: 0.1357 L

3rd: 1.41 M

Explanation:

Finding Molar Mass:

SnCl2 = Tin(II) Chloride

Tin has a molar mass of 118.71 g/mol

Chloride has a molar mass of 35.453 g/mol

Chloride*2 = 70.906

118.71 + 70.906 ≈ 189.6 g/mol

Finding Liters of Solution:

L = mL/1000

135.7 mL / 1000 = 0.1357

Finding Molarity:

molarity = moles of solute / liters of solution

M = (36.4g /  189.6g) / 0.1357 L = 1.41 M

Hope this helped ;)

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