contestada

A Ferris wheel has a radius of 80 ft. Two particular cars are located such that the central angle between them is 165 degrees. To the nearest tenth, what is the length of the intercept arc between those two cars on the Ferris wheel?

Respuesta :

Answer: 230.4 feet

Step-by-step explanation:

arc length = circumfrance x fraction of a circle

Β  Β  Β  Β  Β  Β  Β  Β  = [tex]2\pi r[/tex] x [tex]\frac{165}{360}[/tex]

Β  Β  Β  Β  Β  Β  Β  Β  = [tex]\frac{2*\pi*80*165 }{360}[/tex]

Β  Β  Β  Β  Β  Β  Β  Β  = 230.4 feet to nearest tenth

awhitsett08

Answer:

230.4

Step-by-step explanation:

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