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The particle of 2 velocities 10m/s due east and 12m/S in the direction 30N/E. What is the resultant velocity and the direction?

Respuesta :

Answer:

See below

Explanation:

East components are   10    and    12 cos 30   = 20.392 m/s

North component =  12 sin 30 = 6 m/s

Resultant velocity = sqrt ( 20.392^2 + 6^2) = 21.26 m/s

  direction   arc tan   (6/20.392) = 16.4 degrees N of east

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