After sixth half life, there will be 3.13% of the initial Nâ‚‚O concentration.
The amount of time it takes for the Nâ‚‚O concentration to drop to half its starting value is known as the reaction's half life.
We start out with all of the Nâ‚‚O (100% Nâ‚‚O). 50% of Nâ‚‚O will be present after the first half of life, and 25% will be present after the second half of life and so on.
This suggests that after the sixth half life, we will still have 3.13% of the initial Nâ‚‚O concentration.
So, it takes 6 half lives to get 3.13% of the concentration.
I understand the question you are looking for is this:
Nitrous oxide (Nâ‚‚O) is used as an anesthetic (laughing gas) and in aerosol cans to produce whipped cream. It is also a potent greenhouse gas. The decomposition of Nâ‚‚O is first order. It decomposes slowly to Nâ‚‚ and Oâ‚‚:
2Nâ‚‚O(g) --> 2Nâ‚‚(g) + Oâ‚‚(g)
How many half-lives will it take for the concentration of the Nâ‚‚O to reach 3.13% of its original concentration?
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