beasteddemon0123 beasteddemon0123

09-02-2017
Mathematics

contestada

Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than two times the width

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lazypanda lazypanda

09-02-2017

ALGEBRA M8 SOZ

Length = L, Width = W

L = 20 + 2W,
2L + 2W = 610.

then u gotta do some inspiring expression-algebra-maths stuff to work it out :)

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