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Four point charges lie on the vertices of a square with side length L. Two adjacent vertices have charge Q, while the other two have charge -Q. What is the magnitude of the electric field at the center of the square?

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Answer:

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Explanation:

E1=2Ecosθ=[x2+l2]3/22kq(l)   alongAC;E2=2Ecosθ=[x2+l2]3/22kq(l)   alongDB

So, E1⊥E2. Net field is

E0=E12+E22=[x2+l2]3/222kql=2πε0[x2+l2]3/2ql

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