a popular resort hotel has 300 rooms and is usually fully booked. about 6% of the time a reservation is cancelled before the 6:00 p.m. deadline with no penalty. what is the probability that at least 275 rooms will be occupied? use the binomial distribution to find the exact value. a. 0.01 b. 0.96 c. 0.93 d. 0.85

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melrebecca74 melrebecca74 · Answer 1 · 2022-11-11T13:58:53+01:00

When binomial distribution is used, the probability that at least 275 rooms are occupied is 0.96

Option b. is correct

We have the following parameters:

sample, n=300

proportions of rooms reserved, p=6%

We first get the sample mean,

Sample mean=n*p

=300*6%

=18

Now, we get population mean according to binomial distribution, μ'

μ=n-sample mean

=300-18

=282

We get the standard deviation, σ

σ=(sample mean*(1-p))^1/2

=(18*(1-6%))^1/2

=4.11

We now, calculate z-score:

z=(x-μ)/σ, given x should be at least 275

z=(275-282)/4.11

=-1.703

Now, we have p(x>275)=p(z>-1.703)

From z-score of probabilities, we have p(z>-1.703) as 0.95572

So, p(x>275)=0.95572

=0.96

Hence, the probability that at least 275 rooms are occupied is 0.96

To learn more about binomial distribution; click here:

https://brainly.com/question/14697367

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