Respuesta :
There would be a 68% chance that the average blood pressure would be between 193 to 197.
The subset chosen from the larger set to make assumptions is known as a random sample. A range of values is a confidence interval.
We know that,
            E  =  z ( α / 2 )  ×  σ / √n      →  1
As per the given question,
- Blood pressure in a population of very at risk people has an expected value ( x ) Â = Â 195
- Standard deviation ( σ )  =  20
- Number of random samples ( n ) Â = Â 100
For 68% confidence,
                z ( α / 2 )  =  0.9944
Substitute the values in 1,
E  =  z ( α / 2 )  ×  σ / √n
   =  0.9944  ×  20 / √100
   =  0.9944  ×  20 / 10
   =  0.9944  ×  2
E   =  1.9888  ≅  1.99
Let us consider,
⇒  x  -  E   <   μ   <   x  +  E
⇒  195  -  1.99   <   μ   <   195  +  1.99
⇒  193.01   <   μ   <   196.99
⇒  193   <   μ   <   197      ( ∵  193.01 ≅ 193 and 196.99 ≅ 197 )
⇒  μ  =  ( 193 , 197 )
Therefore, A 68% chance that the average blood pressure lies between 193 to 197. Hence Option b is correct.
To know more about confidence interval problems refer to:
https://brainly.com/question/10126826
#SPJ4
The complete question is
Blood pressure in a population of very at risk people has an expected value of 195 and a standard deviation of 20. Suppose you take a random sample of 100 of these people. There would be a 68% chance that the average blood pressure would be between Select one:
a.) 155 to 235
b.) 193 to 197
c.) 175 to 215
d.) 191 to 199
e.) 200 to 230
