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a 0.460 kg mass suspended from a spring oscillates with a period of 1.50 s. how much mass must be added to the object to change the period to 1.90 s?

Respuesta :

The mass must be added to the object to change the period to 1.90s is 0.428Kg.

What is the formula for time periods?

A thing's time period is the length of time needed for it to complete one oscillation. Any wave element's angle displacement in relation to time is known as its frequency. T is the period, and f is the frequency, and the formula for time is T = 1/f. equals c / f, where c is the wave speed (m/s) and f is the frequency (Hz).

A mass of 0.460 kg oscillates with a period of 1.90 s when it is suspended from a spring.

The time period's formula is provided by,

T = 2π √m/k ....(1)

K denotes the spring's constant, and m denotes the mass.

The new duration is specified by,

T' = 2π √m'/K....(2)

where K is the spring constant, and m' is the final total mass following the addition.

Subtract equation (1) from equation (2).

T/T' = √m/m'

Now change the previously mentioned expression with the known terms.

1.5/1.9 = √0.46/m'

To find the value of m', simplify the expression above.

m' = 0.5/0.5625

m' = 0.888kg

Now, we can calculate the mass that must be added to the object to make the period 1.90s:

m' = 0.889 - 0.460

m' = 0.428Kg.

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