a publisher reports that 75% of their readers own a particular make of car. a marketing executive wants to test the claim that the percentage is actually different from the reported percentage. a random sample of 200 found that 68% of the readers owned a particular make of car. state the null and alternative hypotheses. Determine the P value of the test statastic. Round your answer to four decimal places.

In statistical hypothesis testing, null and alternative hypotheses are used.
A test's null hypothesis always predicts that there will be no effect or relationship between variables, whereas the alternative hypothesis states your research prediction of an effect or relationship.

Given that,

p = 0.75

n =200

p^ = 0.68

Testing statistic;

p = 0.75

q = 1 - p

= 1 - 0.75

= 0.25

[tex]Z = \frac{p^ -p }{\sqrt{\frac{p.q}{n} } }[/tex]

= 0.68 - 0.75 / √(0.75 × 0.25)/200

= -2.2861

Z = -2 .29

p value = 2 × (Z ≤ -2.29 )

= 2 × 0.0110

p value = 0.0220

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