Let width=x m so length=3x-7 Since area =66m^2 L×B=66 (3x-7)×x=66 3x^2-7x=66 3x^2-7x-66=0 3x^2-(18-11)x-66=0 3x^2-18x+11x-66=0 3x(x-6)+11(x-6)=0 So (x-6)(3x-6)=0 So x=2 and x=6 If x=2 Width=2 Length=2×3-7=-1 So this value of x does not exist because length cannot be negative