Respuesta :
Given:
Number of students in the computer training institute = 625 students
Course fee per student = $400
Rate = 50 addt'l students per $20 reduction
Total sales = (625+50x) * ($400-20x)
if reduced by $20, sales = 256500
            $40, sales = 261000
            $60, sales = 263500
            $80, sales = 264000
            $100, sales = 262500
The maximum reduction to maximize sales is $80 or $320 per student and 825 students.Â
Number of students in the computer training institute = 625 students
Course fee per student = $400
Rate = 50 addt'l students per $20 reduction
Total sales = (625+50x) * ($400-20x)
if reduced by $20, sales = 256500
            $40, sales = 261000
            $60, sales = 263500
            $80, sales = 264000
            $100, sales = 262500
The maximum reduction to maximize sales is $80 or $320 per student and 825 students.Â