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Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if his square of compost has a side length that is 8 times longer?

Respuesta :

64,000 I believe. What I did was find the area so 4*4 =16. 1000/16 = 62.5 earthworms per square foot. So if the side is 8 times longer then 8*4= 32 feet per side and to find the area of that it's 32*32 = 1024 feet squared. So 62.5 * 1024 =64,000

Answer:

The answer is 64000.

Step-by-step explanation:

Given is -

Hiram raises 1000 earthworms in a square of compost 4 ft by 4 ft.

When the square of compost has a side length that is 8 times longer, means the area will increase by a factor of [tex]8\times8=64[/tex] times.

So, total earthworms will be = [tex]1000\times64=64000[/tex]