Respuesta :

konrad509
[tex]9x^2=1\\ x^2=\dfrac{1}{9}\\ x=-\dfrac{1}{3} \vee x=\dfrac{1}{3}[/tex]
[tex]9x^2 = 1 \\ \frac{9x^2}{9} = \frac{1}{9} [/tex]

[tex]x^2 = \frac{1}{9} \\ \sqrt{ \frac{1}{9} } = 1/3[/tex], [tex]- 1/3[/tex]