m₀(CO₂)=8.8*10² g
m(LiOH)=3.5*10⁴ g
x=9 d
2LiOH + CO₂ = Li₂CO₃ + H₂O
m(CO₂)=M(CO₂)m(LiOH)/2M(LiOH)
N=m(CO₂)/xm₀(CO₂)=M(CO₂)m(LiOH)/{2M(LiOH)xm₀(CO₂)}
N=44.01*3.5*10⁴/{2*23.95*9*8.8*10²}=4
The maximum number of people is 4.
It is also possible the reaction:
Li₂CO₃ + CO₂ + H₂O = 2LiHCO₃
