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The Ksp of AgCl is 1.8 × 10–10. How do you know that mixing equal amounts of 0.04M solution of AgNO3 and 0.002M solution of NaCl will lead to the formation of a precipitate?

Respuesta :

AgNO₃ + NaCl = NaNO₃ + AgCl↓

c(AgNO₃)=0.04 mol/L
c(NaCl)=0.002 mol/L  ⇒ n(AgCl)/L=0.002 mol/L

Ksp=[Ag⁺][Cl⁻]
the solubility of silver chloride
√Ksp=1.34*10⁻⁵ mol/L

n(AgCl)/L>√Ksp   the precipitate of silver chloride is formed

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