Respuesta :
Part (a)
Let h = Ā depth of water surface from the top of the well, m
Because the stone is dropped, its initial velocity is zero.
Let tā = Ā time for the stone to drop, s
Then
h = (1/2)*(9.8 m/s²)*(tā s)²
tā =Ā ā(h/4.9) s = 0.4518āh s
The velocity of sound is 336 m/s.
The time for the sound wave to travel from the water surface to the top of the well is
tā = h/336 m/sĀ
Because the time before the sound is heard is 2.4 s, therefore
tā + tā = 2.4
0.45181āh + h/336 = 2.4
Multiply through by 336.
151.8082āh + h = 806.4
h - 806.4 = -151.8082āh
h² - 1612.8h + 6.5028 x 10āµ = 2.3046 x 10ā“h
h² - 2.4659 x 10ā“h + 6.5028 x 10āµ = 0
Solve with the quadratic formula.
h = 0.5[2.4659 x 10ā“ +/- 2.4606 x 10ā“]
Ā Ā = 24632 m or 26.5 m
Test the two answers.
When h = 24632,
Ā Ā tā = 0.4518ā(24632) = 70.9 s (Not acceptable)
When h = 26.5 m,
Ā Ā tā = 0.4518ā(26.5) = 2.3258 s, tā = 26.5/336 = 0.0789 s,
Ā Ā tā+tā = 2.4 s (CORRECT)
Answer: Ā h = 26.5 m
Part (b)
If travel time for the sound is ignored, then
0.4518āh = 2.4
h = (2.4/0.45118)² = 28.2 m
The percent error is 100*[(28.2 - 26.5)/26.5] = 6.42%
Answer: The error is Ā 6.4%
Let h = Ā depth of water surface from the top of the well, m
Because the stone is dropped, its initial velocity is zero.
Let tā = Ā time for the stone to drop, s
Then
h = (1/2)*(9.8 m/s²)*(tā s)²
tā =Ā ā(h/4.9) s = 0.4518āh s
The velocity of sound is 336 m/s.
The time for the sound wave to travel from the water surface to the top of the well is
tā = h/336 m/sĀ
Because the time before the sound is heard is 2.4 s, therefore
tā + tā = 2.4
0.45181āh + h/336 = 2.4
Multiply through by 336.
151.8082āh + h = 806.4
h - 806.4 = -151.8082āh
h² - 1612.8h + 6.5028 x 10āµ = 2.3046 x 10ā“h
h² - 2.4659 x 10ā“h + 6.5028 x 10āµ = 0
Solve with the quadratic formula.
h = 0.5[2.4659 x 10ā“ +/- 2.4606 x 10ā“]
Ā Ā = 24632 m or 26.5 m
Test the two answers.
When h = 24632,
Ā Ā tā = 0.4518ā(24632) = 70.9 s (Not acceptable)
When h = 26.5 m,
Ā Ā tā = 0.4518ā(26.5) = 2.3258 s, tā = 26.5/336 = 0.0789 s,
Ā Ā tā+tā = 2.4 s (CORRECT)
Answer: Ā h = 26.5 m
Part (b)
If travel time for the sound is ignored, then
0.4518āh = 2.4
h = (2.4/0.45118)² = 28.2 m
The percent error is 100*[(28.2 - 26.5)/26.5] = 6.42%
Answer: The error is Ā 6.4%