The table below shows four systems of equations:

System 1 4x βˆ’ 5y = 2, 3x βˆ’ y = 8

System 2 4x βˆ’ 5y = 2, 3x βˆ’ 2y = 1

System 3 4x βˆ’ 5y = 2, 3x βˆ’ 8y = 4/

System 44x βˆ’ 5y = 2, 10x βˆ’ 9y = 4

Which pair of systems will have the same solution?

System 1 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 1 to two times the second equation in system 1


System 1 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 1 to three times the second equation in system 1


System 2 and system 4, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2


System 2 and system 4, because the second equation in system 4 is obtained by adding the first equation in system 2 to three times the second equation in system 2

Respuesta :

To determine which system of equations would have the same solution, we evaluate each system of equations.

System 1 4x βˆ’ 5y = 2, 3x βˆ’ y = 8
x = 38/11
y = 26/11

System 2 4x βˆ’ 5y = 2, 3x βˆ’ 2y = 1
x = 1/7
y = -2/7

System 3 4x βˆ’ 5y = 2, 3x βˆ’ 8y = 4
x = -4/17
y = -10/17

System 4 4x βˆ’ 5y = 2, 10x βˆ’ 9y = 4
x = 1/7
y = -2/7


Therefore, the correct answer is option 3.Β 
System 2 and system 4 are equal, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2.

Β  Β  Β 4xβˆ’ 5y = 2Β 2( 3x βˆ’ 2y = 1)
-----------------------Β  Β  10x - 9y = 4

Answer:

its the last one hope this helps