romero8197 romero8197

07-10-2015
Mathematics

contestada

what is the inverse one to one function of f(x) = square root of x-2???

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Panoyin Panoyin

08-10-2015

[tex]f(x) = \sqrt{x - 2} \\y = \sqrt{x - 2} \\y^{2} = (\sqrt{x - 2})^{2} \\y^{2} = x - 2 \\x^{2} = y - 2 \\x^{2} + 2 = y \\x^{2} + 2 = f^{-1}(x)[/tex]

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