HELP!!! you dont have to answer all the questions at least the first one!!!
57x^5 / 19x^2
What is the excluded value(s) of the variable?
How did you you find the value?
and
why it works?

Respuesta :

57/19 = 3
x^5 / x^2 = x^(5-2) = x^3

so 
57x^5 / 19x^2 = 3x^3

answer
3x^3