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The general form for a compound interest function is B(t)=P(1+r/n)^nt . Assuming that n=1 , rewrite the compound interest equation B(t)=900(1.185)^t  in the general form. Using your rewritten equation, what is the percent rate of change?

Respuesta :

The formula [tex]B(t)=P(1+\frac{r}{n})^{nt}[/tex], for n=1 becomes [tex]B(t)=P(1+\frac{r}{1})^{1\cdot t}=P(1+r)^t[/tex].

Comparing [tex]B(t)=P(1+r)^t[/tex] with [tex]B(t)=900(1.185)^t[/tex], we see that 

P=900, and 1+r=1.185, which means that r=0.185.


r=0.185 can be written as 18.5%, as a percentage.


Answer: 18.5%

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