Two containers, A and b begin with equal volumes of liquid. 120 mL is then poured from a to B. Container b now contains four times as much liquid as A. Find the volume of liquid left in container a at the end
Let n be the amount of liquid initially in A and B. Then 4(n-120)=n+120 4n-480=n+120 3n=600 n=200 Both containers originally held 200 ml. Container A has 80 ml left after the transfer; B has 320 ml in it ☺☺☺☺
