Find the orbital period (in years) of an asteroid whose average distance from the sun is 27
a. u. only enter the number, not the units

Respuesta :

Using Kepler's third law which is defined as the square of the average distance is directly proportional to the cube of the period. It is expressed as P^2 = a^3, Given that the a = average distance is given, the period would be much easier to compute. P = sqrt(27^3) = 140