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How many grams of calcium phosphate can be produced when 89.3 grams of calcium chloride reacts with excess sodium phosphate?

Unbalanced equation: CaCl2 + Na3PO4 → NaCl + Ca3(PO4)2

Respuesta :

balanced chemical  equation  is
3CaCl2 +2Na3PO4-->6NaCl +Ca3(PO4)2
moles of  CaCl2  =89.3g/[ (35.5x2) +40]=0.805moles
from  the  equation  above  the  ratio  of  CaCl2  to  Ca3(PO4)2  is  3:1  therefore  the  moles  of Ca3(PO4)2  is 0.809/3=0.268moles
mass  is  therefore  0.268  x310.18(R.F.M of   Ca3(PO4)2 ) =83.23grams