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A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below. If the stone hits the water 2.00 seconds later, what is the height of the bridge above the water?

Remember to identify all your data, write the equation, and show your work.

Respuesta :

The height of the bridge above the water is 49.6 m.

Given that,

  • A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below.
  • And,  the stone hits the water 2.00 seconds.
  • The acceleration is [tex]9.8 m/s^2[/tex]

Based on the above information, the calculation is as follows:

[tex]= 15\times 2 + 0.5\times 9.8\times 2^2[/tex]

= 49.6 m

Learn more: brainly.com/question/17429689

The height of the bridge is 49.6 m. The height of the bridge can be calculated by kinematic equation.

 

The height of the bridge can be calculated by this kinematic equation,  

h = ut + ¹/₂gt²

Where,

u - initial velocity  = 15.0 m/s

t - time = 2 sec

g - gravitationa accelaration  = 9.8 m/s²  

Put the values in the equation,

h = (15 x 2) + ¹/₂(9.8)(2²)  

h = 30 + 19.6  

h = 49.6 m

Therefore, the height of the bridge is 49.6 m.

To know more about velocity,

https://brainly.com/question/21432202

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