Let's actually find the roots, using the quadratic formula:
p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
         -1 plus or minus sqrt(1^2-4(1)(3))
Then x = ----------------------------------------------- Â Â Â Â Â
                      2
The discriminant here is negative, so the roots x will be complex:
       -1 plus or minus sqrt(-11)    -1 plus or minus i*sqrt(11)
    x = ---------------------------------- = -------------------------------------
             2                         2
These are irrational roots; they cannot be expressed as the ratios of integers.