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One watt (w) is equal to 1 j/s. assuming that 5.0% of the energy output of a 75 w light bulb is visible light and that the average wavelength of the visible light is 550 nm, how many photons are emitted by the light bulb per second?

Respuesta :

lpsdesiray
Ephoton = hc/λ = 6.63E-34Js x 3.00E8m/s / 550E-9m = 3.61E-19J 0.05 x 75J/s x 1s = 3.75J 3.75J x 1photon / 3.61E-19J = 1.04E19 photons. 

Answer:

Not sure.

Explanation:

You may have to use the oppisite operations in order to seek the answer.

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