If x - 1 is a factor, then x - 1 = 0 will be an x - intercept of the function. Which (solve for x) means if 1 is substituted into f(x) the result will be zero. [tex]f(1)=(1)^5+1=2[/tex] This is known as the Remainder Theorem. Since the result is not 0, the statement is false. It actually has a factor of (x + 1)
