I made a diagram from your description.
Notice that booth â ACB and â DCE are vertical angles, and we know that vertical angles are congruent by the vertical angles theorem. Also, since she turned around 90° from B towars D and from D towards E, â ABC and â CDE are right angles, and we also know that right triangles are congruent.
So far we prove that â ACBâ
â DCE and â ABCâ
â CDE, and since both angles are corresponding congruent angles, we just prove that âłABC and âłEDC are similar by the AA postulate.
The corresponding sides we are interested in are AB, BC, ED, and DC:
[tex] \frac{AB}{BC} = \frac{ED}{DC} [/tex]
[tex] \frac{AB}{79} = \frac{57}{23} [/tex]
Now the only thing is cross multiply and divide to find the length of AB:
[tex]AB= \frac{(57)(79)}{23} =195.87[/tex]
We can conclude that the distance from A to B to the nearest whole foot is 196 feet.