Using distance=rate multiplied by time as the formula,Â
mountaineer climbed 1,000 feet at a rate of x feet per hourÂ
1000 = xt1 <--eq.1Â
"He climbed an additional 5,000 feet at a different rate."Â
5000 = x't2 <--eq.2Â
"This rate was 10 feet per hour less than twice the first rate."Â
x' = 2x - 10 <--eq.3Â
We now have 3 equations/expressions to solve for the number of hours:Â
From eq. 1 and 2:Â
Total time = t1 +t2 = tÂ
t = 1000/x + 5000/x'Â
but x' = 2x - 10Â
t = 1000/x + 5000/(2x-10)Â
t = 1000/x + 5000/[2(x-5)]Â
t = 1000/x + 2500/(x-5) <--ANSWER