3. I believe the answer is C & A, arrange the boards so that the diagonals bisects and  are perpendicular. A rhombus is a Quadrilateral with all its sides equal to each other. The diagonals of a rhombus are perpendicular to each other and bisects each other.
4.The corresponding pairs of base angles of a trapezoid add up to 180 degrees, (they are supplementary), While all the angles (the four angles add up to 360 degrees)
Therefore; in this case the two angles are equal
  hence, 19x + 8 = 11x+16  solving for x
              x = 1
substituting x in either of the expression
The angle = 27 °
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5. The diagonals of a rhombus bisects each other at right angles; the are perpendicular,
hence,
m∠1= 10x = 90
         x = 9
m∠2 = x + y =90
but x = 9,
thus, y = 81
m∠3 = 5z= 90
       z =18
10. A kite is a Quadrilateral with two equal sides and the other two sides equal.Â
thus, y-4 = 5x+2Â Â and x +22 = 3x +10
solving for x
x+22 = 3x +10
  2x = 12
   x = 6
y-4 = 5x +2
 y-4 = 5(6) +2
   y = 36.
11.a. RHOM is a Quadrilateral with four equal sides
   b. The four sides RH, OH, OM, and RM are equal, They are all congruent
   c  HM and HM is the diagonal, which forms the corresponding sides of triangle MRH and triangle MOHÂ
   d. Triangle MRH and triangle MOH are congruent, SSS, and similar to each other. Â
           Â