How much money does the average professional football fan spend on food at a single football game? that question was posed to 10 randomly selected football fans. the sample results provided a sample mean and standard deviation of $14.00 and $2.50, respectively. use this information to construct a 90% confidence interval for the mean?

Respuesta :

Hi!

When the mean ([tex]\bar{x}[/tex]), the number of samples (n) and standard deviation (σ) are known, you can apply the following equation to determine confidence intervals. The value of z at 90% confidence can be found in tables (It is 1,645).

[tex](\bar{x}-z* \frac{\sigma}{ \sqrt{n} },\bar{x}+z* \frac{\sigma}{ \sqrt{n} }) \\ \\ (14-1,645* \frac{2,50}{ \sqrt{10} },14+1,645* \frac{2,50}{ \sqrt{10} } \\ \\ (12,70\$;15,30\$) [/tex]

Have a nice day!