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A can of soup is in the shape of a cylinder. The diameter of the can is 8 centimeters, and the height is 10 centimeters. What is the surface area of the can, rounded to the nearest hundredth square centimeter? (Use 3.14 for π.) 351.68 cm 2 251.2 cm 2 502.4 cm 2 100.48 cm 2

Respuesta :

Answer:

The surface area of the can is [tex]351.68\ cm^{2}[/tex]

Step-by-step explanation:

we know that

The surface area of a cylinder (can of soup) is equal to

[tex]SA=2\pi r^{2}+\pi Dh[/tex]

we have

[tex]r=8/2=4\ cm[/tex] ----> the radius is half the diameter

[tex]D=8\ cm[/tex]

[tex]h=10\ cm[/tex]

substitute the values

[tex]SA=2(3.14)(4^{2})+(3.14)(8)(10)[/tex]

[tex]SA=100.48+251.2=351.68\ cm^{2}[/tex]

Answer:

351.68 is ur answer

Step-by-step explanation: