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Unit 3 Mid

What is the equation of a line that passes through the point (4,2) and is perpendicular to the line whose equation is y = x/3 - 1

Question 6 options:

y = -3x + 14


y = x/3 + 14


y = 3/x + 23

y = -3/x + 23

Respuesta :

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Find Slope :
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y = x/3 - 1
Slope = 1/3

Perpendicular Slope = - 3

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Equation :
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y = mx + b
y = -3x + b
At (4, 2)
2 = -3(4) + b
b = 14

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Equation :
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y = -3x + 14

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