A possible mechanism for the overall reaction br2 (g) + 2no (g) → 2nobr (g) is no (g) + br2 (g) nobr2 (g) (fast) nobr2 (g) + no (g) k2→ 2nobr (slow) the rate law for formation of nobr based on this mechanism is rate = ________. a possible mechanism for the overall reaction br2 (g) + 2no (g) 2nobr (g) is no (g) + br2 (g) nobr2 (g) (fast) nobr2 (g) + no (g) 2nobr (slow) the rate law for formation of nobr based on this mechanism is rate = ________. k1[br2]1/2 (k2k1/k-1)[no][br2]2 (k1/k-1)2[no]2 k1[no]1/2 (k2k1/k-1)[no]2[br2]

Respuesta :

The overall reaction is:
Brā‚‚(g) + 2 NO(g) ↔ 2 NOBr(g)
rate law = k [Brā‚‚][NO]²

The first step of the overall reaction is:
NO(g) + Brā‚‚(g)Ā  Ā K₁⇄⇄K-1Ā  NOBrā‚‚(g)
rate law 1 = k₁ [Brā‚‚][NO] orĀ 
rate law 2 = k-1 [NOBrā‚‚]

The second step of the overall reaction is:
NOBrā‚‚(g) + NO(g)  →K₂→ 2 NOBr
rate law 3 = kā‚‚[NOBrā‚‚][NO]

So, rate law of overall reaction can be obtained as follows:
(rate law 1)*(rate law 3) / (rate law 2)
= [(k₁[Brā‚‚][NO])* (Kā‚‚[NOBrā‚‚][NO])] / k₋₁[NOBrā‚‚]
= [k₁kā‚‚/k₋₁][NO]²[Brā‚‚]
So the correct answer is:
[k₁kā‚‚/k₋₁][NO]² [Brā‚‚]