Ethene on combustion reaction produces COâ‚‚ and Hâ‚‚O,
           C₂H₄ + 3 O₂  →  2 CO₂ + 2 H₂O
According to Equation,
       28.05 g (1mole) C₂H₄ produced = 88 g (2 mole) of CO₂
So,
           100 g of C₂H₄ will produce = X g of CO₂
Solving for X,
                   X = (100 g × 88 g) ÷ 28.05 g
                   X = 313. 72 g of CO₂